2021 NABTEB GCE Physics Practical Answers [19th November]

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NABTEB NOV/DEC GCE 2021 FREE PHYSICS PRACTICAL (PHY) QUESTION AND ANSWER ROOM

Friday 19th November, 2021
Alternative to Physics Practical (9:00am-11:45am)

NABTEB NOV/DEC GCE PHYSICS PRACTICAL ANSWERS 2021:

A. O'LEVEL NABTEB GCE CHEMISTRY PRACTICAL ANSWERS

(1)
TABULATE
S/N; 1| 2| 3| 4| 5|

L(cm); 75.00| 75.00|75.00| 75.00| 75.00|

h(cm); 7.10| 8.40| 10.50| 12.20| 15.15|

t(cm); 2.20| 2.00| 1.80| 1.60| 1.40|

t²(s²); 4.84| 4.00| 3.24| 2.56| 1.96|

t²(cm²); 5625| 5625| 5725| 5625| 5625|

x=l²/h(cm); 792.25| 669.64| 535.71| 461.07| 371.29|

(1vi)
Slope = ∆X/∆t²
S = Y1 - Y2/X2 - X1
= 1090 - 300/7 - 1.4
S = 790/5.6 = 141.071cm/s²

(1vii)
Evaluate K = S/2
K = 141.071/2
K = 70.536cm/s²

(1viii)
(i) I would ensure error due to parallax were avoided while taking reading from the metre rule
(ii) I would ensure that a solid sphere allowed to roll down inclined plane without external disturbance

(1x)
Graphics


(1bi)
(i) The limiting frictional force(F) is directly proportional to the normal reaction (N) exerted by the surface.
F ∝ N = f=μN
(ii) The kinetic frictional force (F) is directly proportional to the normal reaction (N) exerted by the surface

(1bii)
(i) By lubrication
(ii) Streamlined body
(iii) Make surface smooth by grinding
(iv) Use rolling friction instead of sliding friction
(v) Use fluid friction friction instead of the dry friction
(vi) Reduce contact between surfaces by electrostatic magnetic levitation

(1biii)
Given that:
M=40kg, g=10m/s², θ=40°
f=μR
f= mgsinθ
R= mgcosθ
μ= mgsinθ/mgcosθ
= sinθ/cosθ
μ= tanθ
= tan40
μ= 0.84
==============================

(3)
S/N; 1| 2| 3| 4| 5|

Io(A); 0.27| 0.23| 0.20| 0.18| 0.15|

Va(v); 1.80| 1.50| 1.40| 1.20| 1.00|

Io(A); 0.44| 0.40| 0.34| 0.27| 0.25|

VB(v); 1.30| 1.20| 1.00| 0.90| 0.70|

(3x)


(3vii)
Slope(Sa) = ∆Va/∆Io
Sa= Y1 - Y2/X2 - X1
Sa= 2.0 - 1.0/0.3 - 0.15
Sa= 1/0.15 = 6.667
Sa= 6.667V/A
Slope(Sb)= y2 - y1/x2 - x1
Sb= 2.3 - 1.0/0.8 - 0.34
Sb= 1.3/0.46 = 2.826
Sb= 2.826V/A

(3viii)
(i) I would ensure tight connections
(ii) I would ensure that the key is open when not taking the reading to avoid running down of cells
(iii) I would ensure error due to parallax when reading the ammeter and voltmeter were avoided

(3bi)
The slope of S1 and S2 gives the information about the resistance of the circuit

(3bii)
Voltmeter is considered to have an infinite resistance because it is always connected in parallel with the branch where voltage has to be measured

(3biii)
I= 3A, E= 9v
1/R = 1/R1 + 1/R2
= 1/6 + 1/3 = 3/6
R= 6/3 = 2Ω
I = E/R+r
I(R+r) = E
R+r = E/I
r= E/I - R
r= 9/3 - 2
r= 3-2 = 1Ω
r= 1Ω


B. ADVANCED NABTEB GCE CHEMISTRY PRACTICAL ANSWERS





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